UHS MDCAT 2019 PAPER

MDCAT PAPER (PART 17)

1. Work done due to centripetal force for circular motion will be:

 
 
 
 

2. If we give a direct current to the transformer’s primary coil, then there will be:

 
 
 
 

3. The value and units of the Plank constant ‘h’ can be expressed as:

 
 
 
 

4. A negligible small current between input terminals of the operational amplifier is because of:

 
 
 
 

5. If a conductor of length 7m is placed in a magnetic field of strength 0.3T carrying current 1A, parallel to the field. What will be the force acting on it due to this magnetic field?

 
 
 
 

6. The horizontal component of Earth magnetic flux density is 1.8×10-6 T. The current in a horizontal cable is 160A. Calculate the maximum force per unit length?

 
 
 
 

7. If we change the magnetic flux linking a coil by rotating the coil in a constant magnetic field, the rate of change of this flux is:

 
 
 
 

8. Electric field strength of a point charge is E and electric potential is V at a distance r from point charge. What is the electric potential at a point for same point charge where electric field strength is E/4?

 
 
 
 

9. In simple harmonic motion acceleration will be maximum when object is at:

 
 
 
 

10. Calculate the energy of a photon of frequency 3.0 x 1018 Hz.

(h = 6.63 x 10^-34)

 
 
 
 

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Comments 1

  • in question no 10
    the type of energy reduced by the enzymes for biological reactions to occur is called ACTIVATION ENERGY
    at here the correct answer is active energy which is wrong

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