part 10 question no 2 must be HCl due to the reason that HF is showing less bond dissociation energy that HCl and HBr because of max interelectronic repulsion and un availability of d orbital in case of flourine
Thank you, hamna, for visiting mdcat1.com! We greatly appreciate your valuable feedback. HF is the right answer because fluorine is the smallest halogen and forms a stronger bond with hydrogen compared to the other halogens. HF> HCl> HBr> HI
Thank you for visiting mdcat1.com! We greatly appreciate your valuable feedback. We’ve corrected Page 1, Question 9, while Page 2, Question 10 is correct as it stands. If you still have any confusion, please let me know.
Really appreciate your efforts by providing such a valuable stuff free of cost
May Allah grant u the reward of happy and blessed life in both lives
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part 10 question 10 this is the general formula of aldehyde
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part 10 question no 2 must be HCl due to the reason that HF is showing less bond dissociation energy that HCl and HBr because of max interelectronic repulsion and un availability of d orbital in case of flourine
Thank you, hamna, for visiting mdcat1.com! We greatly appreciate your valuable feedback. HF is the right answer because fluorine is the smallest halogen and forms a stronger bond with hydrogen compared to the other halogens. HF> HCl> HBr> HI
I am deeply grateful and really appreciate your philanthropic spirit in offering such valuable content free of cost. JazakAllah
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Please correct page 1 q 9 and pg 2 q 10
The answers are adjective and cardiac muscle
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Part-12 Q3 shouldn’t answer be alkene, bond angle 120⁰ ?
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good effort
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Thank you so much for such a content Allah ap ko hamesha kush rakh aur har mushkil assan farmay
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